Registered: Oct 2010
Location: Ohio
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I believe these examples of different situations help us all apply the proper rules. They have taught me a lot personally on the right way to score situations.

3 dog cast. Dogs, A, B, C.

Turn loose and Dog A is struck and treed 500 yards in. 3 mins gone on the tree dog B is declared struck and treed in the same area as Dog A. 4 mins gone on the tree Dog C is declared struck and treed in the same area.

Cast arrives at the tree and the only Dog treeing is Dog B. Tree is scored plus.

What are the scores of the dogs?

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A- 125-
B-75+
C-50-

Last edited by AAThoundhunter on 06-06-2018 at 08:06 PM

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quote:

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Originally posted by AAThoundhunter
A- 125-
B-75+
C-50-

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quote:

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Originally posted by AAThoundhunter
A- 125-
B-75+
C-50-

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I enjoy these rules discussions as well, until they get drowned with personal opinions instead of staying on course with what the rulebook actually says.

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quote:

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Originally posted by Allen / UKC
I enjoy these rules discussions as well, until they get drowned with personal opinions instead of staying on course with what the rulebook actually says.

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quote:

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Originally posted by Hoosier Man1
Seems simple but I posted this on another board and the replies were 50 % or more wrong and there was a bunch!

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Dog A= -125
Dog B= +150
Dog C= -75
You did not say if the other two, went back on trail, or if the track was finished.

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How do we know he wasn't split from A? Gets his strike and 125? Lol

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They way I read the rules he is only shut out strike points if found on the same tree

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quote:

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Originally posted by Philip
How do we know he wasn't split from A? Gets his strike and 125? Lol

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quote:

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Originally posted by AAThoundhunter
You don’t know if he was split or not that’s why he only gets +75. Once a dog is minused for moving nobody moves up in tree points if you couldn’t tell if they were together or not to begin with. He only gets +75 because he was shut out on strike.

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If C is found split from B I’d give him +50 for the same reason you can’t prove where any dog was from that far, and you don’t know what dog was with A or if they were all split. I don’t know if that’s right or not but how I’d do it.

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If all dogs are at the same tree when you arrive, and only one is barking treed, under rule 4h don't all dogs get plus points if a coon is seen. 4(h) After a dog is declared treed, at least one of the dogs declared treed must bark at least once every two minutes until cast arrives at the tree, or all declared treed at that tree will be minused and the tree will be open again.

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quote:

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Originally posted by AAThoundhunter
If C is found split from B I’d give him +50 for the same reason you can’t prove where any dog was from that far, and you don’t know what dog was with A or if they were all split. I don’t know if that’s right or not but how I’d do it.

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quote:

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Originally posted by J I Allen
If all dogs are at the same tree when you arrive, and only one is barking treed, under rule 4h don't all dogs get plus points if a coon is seen. 4(h) After a dog is declared treed, at least one of the dogs declared treed must bark at least once every two minutes until cast arrives at the tree, or all declared treed at that tree will be minused and the tree will be open again.

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Just wondering so I know in black and white how do you not give strike points and move him up to first tree if dog b is the only one on the tree and you couldn't tell if they weren't spilt for sure thanks

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quote:

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Originally posted by nextcoonhunters
Just wondering so I know in black and white how do you not give strike points and move him up to first tree if dog b is the only one on the tree and you couldn't tell if they weren't spilt for sure thanks

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quote:

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Originally posted by DFred
I'm sure it's in the Advisor but I don't have the copy with me. Anyhow dogs can't be determined split unless judge is 100% sure of such. So, until it is determined, it will be assumed they are together. Just like this senario, when the judge arrived, it couldn't be proven that they were ever split so the assumption has to be that they were at one time together.

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