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Richard Lambert
UKC Forum Member

Registered: Aug 2004
Location: Chattanooga, Tn
Posts: 22586

Rule Question

Dog A is struck for 100. Dog B is struck second for 75. Dog C is struck third for 50. Dogs A and B are called treed at the same time and split first and second and are each awarded 100. Dog A leaves, goes back on track and is minused 100. Dog C is now declared treed with Dog B. What points does Dog C get treed for, 100, 75 or 50?

Last edited by Richard Lambert on 08-05-2019 at 01:50 PM

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Rocketman55
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Registered: Aug 2008
Location: SE Ohio, Glouster
Posts: 2244

Well as I see it, much of this depends on where dog C was declared treed. If Dog C was declared treed with Dog B then dog C get awarded 50 tree points, if dog C is CERTAINLY split from dog B then dog C is treed for 125 under UKC rules.

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Old Post 08-05-2019 04:44 AM
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Allen / UKC
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Registered: Nov 2004
Location: Michigan
Posts: 9278

Nothing changes when it comes to tree points for Dog B. It was called treed tied for first and second (100). That's already been established, unless you're trying to confuse someone. Oh my goodness.... surely not.

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Old Post 08-05-2019 01:39 PM
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CHEWBACH
UKC Forum Member

Registered: Jan 2007
Location: monroeville OH
Posts: 2685

Re: Rule Question

quote:
Originally posted by Richard Lambert
Dog A is struck for 100. Dog B is struck second for 75. Dog C is struck third for 50. Dogs A and B are called treed at the same time and split first and second and are each awarded 100. Dog A leaves, goes back on track and is minused 100. Dog C is now declared treed with Dog B. What points does Dog C get treed for, 100, 75 or 50?
you still on that corn whisky. go back to the cookies.

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Old Post 08-05-2019 07:00 PM
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ringtail
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Registered: Jan 2004
Location: Tennessee
Posts: 2760

75

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