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Another scoring question

4 dog cast dog A struck and treed. Dog B,C,D shut out on strike. Dog B an C are treed. 5 expires and dog D is treed afterwards. Upon arriving dog A is alone and other 3 are together. I know B an C move up to 125 and 75 tree as they were. As judge i put D in at 125 and minus him immediatly for being on closed tree. Cast argues including guy leading that a dog shut out shouldnt go in for 125. The 3 of them agreed he went in for next available with a line thru it. It wasnt gonna affect hunt either way as it was over at this point so no need to argue all night. Looking back and readin the book this morning im thinking he should have been minused 125 then awarded next available an scored accordinvly.

U ran 5 on 1 tree .even thou u had 2 trees to score.
I understand a''s tree had xpired .
U arrive and find b,c, & d split after a's tree was closed.
Hmmmmmmm

How can u justify minusing D"s tree ? It's split. Did u put a separate 5 on b & c tree ?

The "other three" need to read the rules on the back of the card. It is fairly straightforward. I don't understand why handlers don't do that. They would rather score situations the way they "think" that they should be scored instead of just turning the card over and reading the rule.

Rule 4k dog will be scored as a split that it left then scored on closed tree. Thats 125 minus then scored accordingly the way i see it. No need to run a seperate 5 on any especially since we all thought they were together till we were nearly to them

There u go thinking again.....u minused D, based on A tree time .....

Running 5 on D was irrevelant. By the rule he is implied split when found on B an C tree he is minused his 125 and scored with them. Would it have been any different if i had ran a 5 on D and found him at B an C tree before his 5 was up. How bout found him there after his 5 was up. Running 5 on dog D is a moot point. He left implied split tree

quote:

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Originally posted by rooster731
Running 5 on D was irrevelant. By the rule he is implied split when found on B an C tree he is minused his 125 and scored with them. Would it have been any different if i had ran a 5 on D and found him at B an C tree before his 5 was up. How bout found him there after his 5 was up. Running 5 on dog D is a moot point. He left implied split tree

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Yes 5 was up on dog B.

quote:

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Originally posted by rooster731
Yes 5 was up on dog B.

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Whats convenient ? B and C were on dog A 5 from 800 yards and a 25 mph wind there was no way to tell they were split. Dog D was pitched with a minute left in the hunt. We were another 8 or 10 minutes walking to them. Do you have anything to say worth hearing or just being hard to deal with?

Who is to say b and C didn’t move to D’s tree.

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Could have but if dog D had been treed that quick he should have been treed in inside the 5.

Sounds like a cluster.

It was one of those situations that seldom come up where everyone scratches their head. Fortunately it didnt affect the outcome. Everyone left satisfied but still wondering

What I have to say has already been said .Your revision does make a different nontheless .

quote:

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Originally posted by Ryan Karl
Who is to say b and C didn’t move to D’s tree.

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Oh my goodness, rule plainly states that if you tree your dog after tree is closed then he better be on a tree by himself or he will be minused 125.....no ifs ands, buts or maybes. Rule was put in place to stop all of the arguing and lawyering. And yet some are still trying to argue.